Find the lesser 9 consecutive numbers and greater than 10 such that when dividing each of them by its last number, the result is always an integer.

For example, if we start with 31 we have that 31/1 is an integer division, 32/2 is also an integer, 33/3 as well, but by dividing 34/4 we don't get an integer.

#### Solution

**They are the numbers from 2521 to 2529**.

First we get the least common multiple from 1 to 9, which is 2520 and then we add the numbers from 1 to 9. By definition, each of them will be divisible by the last figure.